Just a few seconds ago I had an idea how to generalize both funcoids and reloids.

Consider

This axiomatic system is so powerful that it allows to define $latex \langle f\rangle$ for a funcoid $latex f$:

$latex \langle f\rangle\mathcal{X} = \mathrm{im}(f\circ(1^\mathfrak{F}\times^\mathsf{FCD}\mathcal{X}))$.

One Response

  1. However this axiomatic system is probably too weak to prove $latex \langle g\rangle\langle f\rangle\mathcal{X} = \langle g\circ f\rangle\mathcal{X}$. We need additional axioms.

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