### Funcoids are filters?

I am not doing math research this month (because a bug in TeXmacs software which I use for writing my book and articles). I instead do writing some free software not to waste my time.

But today (this hour) I unexpectedly had a new interesting idea about my math research:

Let denote $latex Q$ the set of finite joins of funcoidal products of two principal filters.

Conjecture The poset of funcoids is order-isomorphic to the set of filters on the set $latex Q$ (moreover the isomorphism is (possibly infinite) meet of the filter).

If proved positively, this may reveal new properties of funcoids and probably solve some of my open problems.

## 3 thoughts on “Funcoids are filters?”

1. Clarification to my previous comment. To disprove the conjecture it is enough to prove that $latex \bigsqcap^{\mathsf{FCD}} \mathcal{A} = \bigsqcap^{\mathsf{FCD}} \mathcal{B}$ (that is $latex \left\langle \bigsqcap^{\mathsf{FCD}} \mathcal{A} \right\rangle a = \left\langle \bigsqcap^{\mathsf{FCD}} \mathcal{B} \right\rangle a$ for every ultrafilter $latex a$) does not imply $latex \mathcal{A} = \mathcal{B}$.