📚 Recommended Mathematics Books

Topology (Munkres)  |  General Topology (Engelking)  |  Counterexamples in Topology  |  Rudin's Analysis

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I’ve proved: There exists a filter which cannot be (both weakly and strongly) partitioned into ultrafilters.

It is an easy consequence of a lemma proved by Niels Diepeveen (also Karl Kronenfeld has helped me to elaborate the proof).

See the preprint of my book.