New conjecture about funcoids

Conjecture \langle f \rangle \bigsqcup S = \bigsqcup_{\mathcal{X} \in S} \langle f \rangle \mathcal{X} if S is a totally ordered (generalize for a filter base) set of filters (or at least set of sets).

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  1. Pingback: A counterexample to my recent conjecture | Victor Porton's Math Blog

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